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9x^2-54=144
We move all terms to the left:
9x^2-54-(144)=0
We add all the numbers together, and all the variables
9x^2-198=0
a = 9; b = 0; c = -198;
Δ = b2-4ac
Δ = 02-4·9·(-198)
Δ = 7128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7128}=\sqrt{324*22}=\sqrt{324}*\sqrt{22}=18\sqrt{22}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{22}}{2*9}=\frac{0-18\sqrt{22}}{18} =-\frac{18\sqrt{22}}{18} =-\sqrt{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{22}}{2*9}=\frac{0+18\sqrt{22}}{18} =\frac{18\sqrt{22}}{18} =\sqrt{22} $
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